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SILProof

Level measurement · hydrostatic head

DP level transmitter calculator

Work out the calibration range (LRV and URV) of a DP level transmitter, and the differential pressure and current at any level.

Examples
Installation

Relative to water at 4 °C (1000 kg/m³). Use the SG at operating temperature.

mm
%
Advanced
mm

The filled impulse lines below the taps add a constant head to the zero.

Process liquid, or the seal fill for capillary seals.

Calibration range (LRV → URV)True zero

0 → 196.13 mbar

Span 196.13 mbar for 2,000 mm of liquid at SG 1

LRV (0 %, 4 mA)
0 mbar
URV (100 %, 20 mA)
196.13 mbar
Span
196.13 mbar
At 50 % level (1,000 mm)
98.066 mbar · 12 mA

Working

  1. ΔP = PHP − PLP; head of liquid = SG × ρw × g × h with ρw g = 9.80665 kPa per metre of water
  2. PHP(h) = 1 × (0 mm + h)
  3. PLP = atmosphere, the same on both sides (gauge 0)
  4. LRV = ΔP(h = 0) = 0 m H₂O = 0 mbar
  5. URV = ΔP(h = 2,000 mm) = 2 m H₂O = 196.13 mbar
  6. At 50 %: ΔP = 98.066 mbar → I = 4 + 16 × (98.066 − 0) / 196.13 = 12 mA

What the calculator is for

A DP transmitter measures level as the hydrostatic head of liquid above its high-pressure (HP) tap: ΔP = SG × ρw × g × h. The range you configure depends on where the taps and transmitter sit and on what fills the low-pressure (LP) side. Getting it wrong shifts every level reading, so calculate it before configuring the transmitter.

  • Open tank: LP side vented to atmosphere.
  • Closed tank, dry leg: LP impulse line full of vapour or gas, so the vessel pressure cancels.
  • Closed tank, wet leg: LP line full of liquid (condensate or seal fill). Its head acts against the process head, giving a negative LRV: an elevated zero.

Worked example

A closed vessel holds a liquid of SG 0.85. The 0 % level is 300 mm above the HP tap, the span is 1,500 mm and the LP tap is 2,200 mm above the HP tap with a wet leg of water (SG 1).

At 0 %: ΔP = 0.85 × 0.3 m − 1.0 × 2.2 m = −1.945 m H₂O = −190.74 mbar. At 100 %: 0.85 × 1.8 m − 2.2 m = −0.67 m H₂O = −65.705 mbar. The span is 125.03 mbar; the transmitter is ranged −190.74 to −65.705 mbar. Load this case from the examples above to see each step.

Head of one metre of water

Pressure of 1 m of water (ρ = 1000 kg/m³, g = 9.80665 m/s²)
Unit1 m H₂O =
mbar98.0665
kPa9.80665
psi1.42233
inH₂O39.3701
mmH₂O1,000

Common mistakes

  • Design SG instead of operating SG. Density changes with temperature and composition; a 5 % SG error is a 5 % level error.
  • Forgetting the transmitter mounting height. A transmitter below the HP tap sees the extra head of the filled impulse line: a suppressed zero.
  • A wet leg that drains or a dry leg that fills. Both move the zero. Condensing vapours need a wet leg or seals, and the wet leg must stay full.
  • The LP tap below the maximum level. The process then floods the LP leg and the measurement no longer works.

Basis

Hydrostatic pressure p = ρgh with the conventional water density 1000 kg/m³ and standard gravity 9.80665 m/s², the definitions behind mmH₂O and inH₂O (4 °C). Some transmitters use inH₂O at 60 °F or 68 °F; check the unit configured in the device.

Frequently asked questions

How do I calculate LRV and URV for a DP level transmitter?

LRV is the differential pressure at 0 % level and URV at 100 %. For an open tank with the tap at 0 %, LRV = 0 and URV = SG × span in water column; wet legs and mounting heights shift both by the same constant.

What is the difference between zero elevation and zero suppression?

Elevation means the LRV is negative, typically from a wet leg on the LP side. Suppression means the LRV is positive, typically from a transmitter mounted below the HP tap.

When do I need a wet leg?

When the vapour above the liquid condenses in the LP impulse line. A deliberately filled wet leg, or remote seals, keeps the LP head constant.

Does the vessel pressure affect the DP level reading?

Not with a correctly filled dry or wet leg: the vessel pressure acts on both sides of the transmitter and cancels.

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